Laboratory #4 Nodal Analysis

Today, we just used the method of nodal analysis to figure out the voltage of each nodal and test it out the error. In another way, we also could use the voltage of each nodal to figure out the power supply.

First of this lab, we established two equation which were 0-V2/Rc1= V2-V1/Rc1+V2-V3/Rc2 and
V2-V3/Rc2=V3/RL2+V3-V4/Rc3. So we had V2=10.25V and V3=8.67V.
Furthermore, we got Ibat1=V1-V2/Rc1=0.0175A, and Ibat2=V4-V3/Rc3=0.0015A which these are the current of the battery. Because the power equal to the current times the voltage, so Pbat1=0.179375W, Pbat2=0.013005W.Then, we did the set up and use the actual equipment to do this experiment that we had Rc1=99.4ohms, Rc2=219ohms, Rc3=223ohms, RL1=995ohms, RL2=999ohms, Vbat1=12.11V and Vbat2=9.08V. We had been through a hard time to measure the value, and we got them all finally that they were Ibat1=17.8mA, Ibat2=1.53mA, V2=10.3V and V3=9.41V. Luckily, these numbers percent error were really small. They are 1.7%, 2%, 0.4% and 8.5%.
For doing the more calculation, the Pbat1= Vb1*Ib1= 12.11V*0.0178A=0.215558W and Pbat2=9.08V*0.00153A=0.013892W.
If the V2=V3=9V, the new set up will be -9V/1000=9-V1/100, and 9/1000+9-V4/220=0. The result will be V1=9.9V which is battery 1 and V4=10.98 which is battery 2.
After finishing this experiment, I learned a couple easy ways for measuring stuff. But i also get touch with a lot of mistake which could occur that makes the lab harder for doing the wrong way.